
How do you solve 2^x = 7? - Socratic
Mar 16, 2016 · x~~2.81 1. Since the left and right sides of the equation do not have the same base, start by taking the log of both sides. 2^x=7 log(2^x)=log(7) 2.
How do you simplify #(x+7)(x+2)#? - Socratic
Mar 19, 2017 · x^2 + 9x + 14 This problem is solved using the FOIL method: Multiply the F irst terms, Multiply the O uter terms, Multiply the I nner terms, Multiply the L ast terms, and add all those products together. So, to foil (x+7)(x+2), use the steps below: First: x * x = x^2 Outer: x * 2 = 2x Inner: x * 7 = 7x Last: 7 * 2 = 14 First + Outer + Inner + Last = x^2 + 2x + 7x + 14 = x^2 + …
How do you solve x^3+7x^2-x-7<0? - Socratic
Jan 29, 2017 · How do you solve quadratic inequality, graph, and write in interval notation #x^2 - 8x + 15 >0
How do you solve 2/x=7/9? - Socratic
Mar 25, 2018 · If we multiply both sides by #color(red)9color(blue)x#, we get: #=>(2(color(red)9cancelcolor(blue)x))/cancelx = (7(cancelcolor(red)9color(blue)x))/cancel9# Now we can simplify and continue solving for #x# .
How do you solve 2x+7= -17? - Socratic
Mar 4, 2018 · x=-12 2x+7= -17 2x= -17-7 2x= -24 (Divide both sides by 2) x=-12. Algebra Linear Equations Two-Step Equations and Properties of Equality
How do I Find P ( 2 < X < 7 )? (Stats) - Socratic
May 16, 2018 · P(2 < X < 7) = 54.43%. The picture is a bit blurry, but it appears as though X is the number of calls over a 1.5 minute interval.
How do you solve 2(x+7)+x=20? - Socratic
#2x+2*7+x=20# Multiply by #7# to get #14# #2x+14+x=20# Add #2x# and #x# to get #3x# #3x+14=20# Since #14# does not contain the variable to solve for, move it to the right side of the equation by subtracting #14# from both sides. #3x=-14+20# Add #-14+20# to get #6# #3x=6# Divide each term by #3# and simplify. Answer : #x=2#
How do you solve #x^2 + 2x-7=0# using the quadratic formula?
Feb 14, 2016 · #color(blue)(x^2+2x-7# This equation is a Quadratic equation (in form #ax^2+bx+c=0#). Use the Quadratic formula:
How do you find the fourth term of #(x+2)^7#? - Socratic
Jan 11, 2017 · 280x^4 Recall that the (r+1)^(th) term T_(r+1) in the expansion of (a+b)^n is given by, T_(r+1)=""_nC_ra^(n-r)b^r.
How do you solve -2<=x-7<=11? - Socratic
Aug 3, 2016 · In interval notation, this is written as x in [5, +oo) For the second condition, you need x to be smaller than or equal to 18. In interval notation, this is written as x in (-oo, 18] This means that the solution interval for the compound inequality must have x greater than or equal to 5 and smaller than or equal to 18.