−2x + y >= 2 x = 0 y = 0 the graph looks like this. the area of the graph that is not shaded is your region of feasibility. the corner points of that region are where the maximum / minimum value of the objective function lies. the objective function is p 5x + 4y the corner points on the graph are: (2.8, 7.6) (.769, 3.538) (5, 1)

|x-2| if x2 The rule is that if the expression within the absolute bars is positive, just remove the bars. Conversely, if negative, put a minus sign in front of the expression after removing the bars. In the given case, since x2, (x-2) is negative,therefore, |x-2|= -(x-2)=2-x

SOLUTION: Solve the equation. (Enter your answers as a comma-separated list. Use n as an integer constant. Enter your response in radians.) (2 sin2 x − 1)(tan2 x − 3

Using the slope of 1/2, move up one space from (0,0) and move to the left two spaces. Plot point (2, 1). From (2,1) move up one space and over two spaces to point (4, 2).. Stating over, go to the y-intercept again. Using the the slope (-1/-2)(same slope, different form). Move down one space and to the left two spaces to point (-2, -1).

An x-intercept (where the function value is 0) is caused by a factor in the numerator that is equal to 0. If there is an x-intercept at x=3, there must be a factor of (x-3) in the numerator. Note that the degree of the numerator at this point is less than the degree of the denominator; so the condition for having a horizontal asymptote of y=0 ...

(2) g(0) = (6*0^2) + 0 + 4 = 0 + 0 + 4 = 4. (3) f'(u) = use the rule of differentiating the fractional function f(u) = The numerator of the derivative will be 1*(u^2-1) - u*2u = -u^2-1. We should calculate it at u= g(0) = 4, so the numerator's numerical value is -4^2-1 = -16-1 = -17.

We will use the "completing the square" method. The polynomial x^2+8x+16 is a perfect square [(8/2)^2=16], so we need to add 16 to both sides of the equation and re-arrange the terms.. . The polynomial y^2-6y+9 is a perfect square, so we need to add 9 to both sides of the equation.. Now write the polynomial expressions in factored form..

Question 1117240: A line l is parallel to the y-axis and passes through the point (2,3). What is its gradient (m) and x-intercept? m= 0 , x= (3,0) m= ∞ , x= (2,0) m= 0 , x= (2,0) m= ∞ , x= (3,0) m= 2 , x= (0,0) how do I figure this out quickly without a graphing calculator? Answer by rothauserc(4718) (Show Source):

Integrating should be fairly trivial because 2x(1-x) = 2x-2x^2 is a polynomial You should find that E[X] = 1/3 in other words, mu = mean = 1/3 ----- The variance is defined as i.e. So we'll need to calculate E(X^2) Once again I'll skip steps. The result you should get is E[X^2] = 1/6 ----- Therefore, Var(X) = variance Var(X) = E[X^2] - ( E[X ...

First let's pull out the GCF x x^5-13x^3+36x = 0 x(x^4-13x^2+36) = 0 Now let's factor x^4-13x^2+36 To do so, we have at least two methods Method 1) Let w = x^2 So w^2 = x^4 Then x^4-13x^2+36 is the same as w^2-13w+36 Through trial and error, that would factor to (w-4)(w-9) Note: -4 and -9 add to -13 and multiply to 36. Then, (w-4)(w-9) = (x^2-4 ...