Jan 5, 2016 · dy/dx = -2sin2x what we have here is a function 2x inside another function cos . This is known as a function of a function. If we differentiate cosx we get - sinx when we differentiate …

Sep 15, 2015 · Calculus Differentiating Trigonometric Functions Derivative Rules for y=cos(x) and y=tan(x)

Mar 7, 2018 · y^((50)) = -2^(50) cos(2x) A fiftieth derivative! Guess we better start going... Zeroth derivative: y = cos(2x) First derivative: y' = -2sin(2x) Second derivative y'' = -4 cos(2x) Wait...

May 9, 2018 · #"differentiate using the "color(blue)"chain rule"# # "given "y=f(g(x))" then"# #dy/dx=f'(g(x))xxg'(x)larrcolor(blue)"chain rule"#

Nov 19, 2015 · Use the Product Rule.. Also, find the derivatives of the two terms first. #d/dx[cosx]=-sinx# #d/dx[cos2x]=-2sin2x#

Jul 4, 2018 · How do you find the derivative of # cos^2(2x)#? Calculus Differentiating Trigonometric Functions Derivative Rules for y=cos(x) and y=tan(x)

Jul 21, 2018 · What is the derivative of #sin(2x)cos(2x)#? Calculus Basic Differentiation Rules Chain Rule. 2 Answers

Oct 20, 2015 · f(x) = ln(cos^2x) = ln((cosx)^2) = 2ln(cosx) f'(x) = 2 1/cosx (-sinx) " " (Chain rule: d/dx(lnu) = 1/u (du)/dx) = -2tanx

Jan 7, 2017 · d/dx(sinxcosx) = cos2x The product rule can be used to differentiate any function of the form f(x) = g(x)h(x

Dec 29, 2016 · Another approach is to simply the expression using the identity: # sin 2theta = 2sinthetacostheta# before starting, which yields a simpler, (but identical) form of the solution: